🚀 Day 22 of My Python Journey – Solved Permutation in String! 💻 Today I worked on checking whether one string’s permutation exists in another string This problem was a great mix of strings + sliding ...
s1_count, s2_count = [0] * 26, [0] * 26 # create empty lists # idea is to store the 26 letters of the alphabet for i in range(len(s1)): # iterate through the first couple letters in s2 so that # we ...
Given two strings ``s1`` and ``s2``, return ``True`` if any permutation of 1. Brute force (O(n·m·Σ)): sort every length-m window of s2 and compare. 2. Optimal — fixed-size window with difference array ...
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